Question on: JAMB Physics - 2022
A reservoir is filled with liquid of density 2000 kgm\(^{-1}\). Calculate the depth at which the pressure in the liquid will be equal to 9100 Nm\(^{-2}\) (g = 10 ms\(^{-2}\))
A
0.262 m
B
0.664 m
C
0.819 m
D
0.455 m
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Correct Option: D
The pressure in a liquid at a certain depth can be calculated using the following formula:
* P = ρgh
Where:
* P = Pressure
* ρ = Density of the liquid
* g = Acceleration due to gravity
* h = Depth
We are given:
* P = 9100 Nm⁻²
* ρ = 2000 kgm⁻³
* g = 10 ms⁻²
We need to find h.
Rearranging the formula to solve for h:
* h = P / (ρg)
Substituting the given values:
* h = 9100 / (2000 \* 10)
* h = 9100 / 2
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