Question on: WAEC Physics - 2001
A resistance thermometer has a resistance of 20(\Omega) at 0oC and 85(\Omega) at 100oC. If its resistance is 52(\Omega)in a medium, calculate the corresponding temperature
A
49.2oC
B
60.6oC
C
80.0oC
D
84.7oC
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Correct Option: A
85(\Omega) ........100oC
52(\Omega) ........(\theta)oC
20(\Omega) ........0oC
(\frac{52 - 20}{85 - 20} = \frac{\theta - 0}{100 - 0})
(\theta = \frac{32 \times 100}{65} = 49.2^oC)
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