Question on: SS2 Physics - Heat and Thermodynamics
A sample of water at 25°C absorbs 4,000 J of heat energy. If the mass of the water is 500 grams, what is the temperature change of the water? The specific heat capacity of water is 4.18 J/g°C.
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We can rearrange the formula Q = m c ΔT to solve for ΔT:
ΔT = Q / (m x c)
ΔT = 4,000 J / (500 g x 4.18 J/g°C)
ΔT ≈ 1.91°C
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