Question on: WAEC Mathematics - 1993
A sector of a circle of radius 9cm subtends angle 120° at the centre of the circle. Find the area of the sector to the nearest cm\(^2\) [Take π = 22/7]
A
75cm2
B
84cm2
C
85cm2
D
86cm2
Ask EduPadi AI for a detailed answer
Correct Option: C
Area of a sector = θ/360 x πr\(^2\)
= 120/360 x 22/7 x 81/1
= 84.86 cm\(^2\)
\(\approxeq\) 85cm\(^2\) (to the nearest cm)
Add your answer
Please share this, thanks!
No responses