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A shooter wants to fire a bullet in such a way ... - JAMB Physics 2006 Question

A shooter wants to fire a bullet in such a way that its horizontal range is equal to three times its maximum height. At the what angle should he fire the bullet to achieve this?
A
68o
B
53o
C
30o
D
45o
correct option: b

Horizontal range = 3 x maxi. height

=> (U2Sin2θ) / g = (3 x U2sin2θ) / 2g

∴sin2θ = 3sin2θ
2

=> 2sinθcosθ = 3sin2θ
2

∴ 4sinθcosθ = 3sin2θ

=> 4cosθ = 3sinθ

sinθ/cosθ = 4/3; => tanθ = 4/3 = 1.3333

θ = tan-1 (1.3333)

= 53o

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