Question on: JAMB Physics - 1991
A spring of force constant 1500Nm-1 is acted upon by a constant force of 75N. Calculate the potential energy stored in the string
A
1.9J
B
2.8J
C
3.45J
D
0.43J
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Correct Option: A
P.E = (\frac{1}{2})Fe
= (\frac{1}{2})(\frac{F}{K})
= (\frac{1}{2}) x (\frac{75 \times 75}{1500})
= 1.9J
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