Question on: JAMB Mathematics - 2008
A student sitting on a tower 68 metres high observes his principal's car at the angle of depression of 20o. How far is the car from the bottom of the tower to the nearest metre?
A
184m
B
185m
C
186m
D
187m
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Correct Option: D
Tan 20o = \(\frac{68m}{x}\)
x tan 20o = 68
x = \(\frac{68}{tan 20}\) = \(\frac{68}{0.364}\)
x = 186.8
= 187m
x tan 20o = 68
x = \(\frac{68}{tan 20}\) = \(\frac{68}{0.364}\)
x = 186.8
= 187m
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