Question on: JAMB Mathematics - 2003
A triangle has vertices P(-1,6), Q(-3, -4) and R(1, -4).Find the midpoint of PQ and QR respectively.
A
(0,-2) and (-1, -4)
B
(-1,0) and (-1,-1)
C
(-2,1) and (0,1)
D
(-2,1) and (-1,-4)
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Correct Option: D
Midpoint of PQ \(\frac{x_2 + x_1}{2};\frac{y_2 + y_1}{2}\\
=\frac{-1+(-3)}{2};\frac{6-4}{2}\\
=\frac{-4}{2};\frac{2}{2}\\
=-2,1\)
Midpoint of QR = \(\frac{x_2 + x_1}{2};\frac{y_2 + y_1}{2}\\ \frac{-3+1}{2};\frac{-4-4}{2}\\ \frac{-2}{2};\frac{-8}{2}\\ -1,-4\)
Midpoint of PQ and QR = (-2,1) and (-1,-4)
Midpoint of QR = \(\frac{x_2 + x_1}{2};\frac{y_2 + y_1}{2}\\ \frac{-3+1}{2};\frac{-4-4}{2}\\ \frac{-2}{2};\frac{-8}{2}\\ -1,-4\)
Midpoint of PQ and QR = (-2,1) and (-1,-4)
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