A trough 12 0cm deep is filled with water of re... - JAMB Physics 1991 Question
A trough 12.0cm deep is filled with water of refractive index \(\frac{4}{3}\). By how much would a coin at the bottom of the trough appear to be displaced when viewed vertically from above the water surface?
A
3.0cm
B
6.0cm
C
9.0cm
D
16.0cm
correct option: a
(\frac{4}{3}) = (\frac{12}{\text {Apparent depth}})
Apparent depth = 9cm
Height by which coin is raised = 12 - 9
= 3cm
Please share this, thanks:
#JAMB #JAMB
Add your answer
No responses