Question on: WAEC Physics - 1991
A water fall is 420m high. Calculate the difference in temperature of the water between the top and bottom of the water fall. Neglect heat loses(g = 10.0m-2 specific heat capacity of water = 4.20 x 10-3 JKg-1 K-1)
A
0.1oC
B
1.0oC
C
42oC
D
100oC
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Correct Option: B
Potential Energy = Heat Energy
mgh = Mc\(\Delta \theta = \frac{gh}{c} = \frac{10 \times 240}{4.20 \times 10^3}\)
= 1.0oC
mgh = Mc\(\Delta \theta = \frac{gh}{c} = \frac{10 \times 240}{4.20 \times 10^3}\)
= 1.0oC
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