Home » Classroom » WAEC Physics 2018 Question

A wire of length 400cm is stretched between two... - WAEC Physics 2018 Question

A wire of length 400cm is stretched between two fixed points. When plucked, its fundamental frequency is 150Hz. Calculate the speed of the wave produced.

A
250\(ms^{-1}\)
B
625\(ms^{-1}\)
C
1200\(ms^{-1}\)
D
1500\(ms^{-1}\)
Ask EduPadi AI...
Correct Option: C

The fundamental frequency \((f_{0})\) = \(\frac{v}{2l}\)

\(f_{0} = 150Hz; l =400cm = 4m\)

\(150 = \frac{v}{2\times 4}\)

\(v = 150 \times 8 = 1200ms^{-1}\)

Please share this, thanks:

#WAEC #WAEC

Add your answer

Notice: Please post responsibly.

No responses