A wire of resistivity 4 40 x 10-5 Omega cm has ... - WAEC Physics 2009 Question
A wire of resistivity 4.40 x 10-5(\Omega) cm has a cross sectional area of 7.50 x 10-4 cm2. Calculate the length of the wire that will be required to make a 4.0(\Omega) resistor
A
82.50 cm
B
68.18cm
C
15.90cm
D
11.95cm
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Correct Option: B
L = (\frac{R.A}{e} = \frac{4 \times 7.50 \times 106{-4}}{4.40 \times 10^{-5}} = 68.18cm)
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