Question on: WAEC Mathematics - 2012
Alfred spent \(\frac{1}{4}\) of his money on food, \(\frac{1}{3}\) on clothing and save the rest. If he saved N72,20.00, how much did he spend on food?
A
N43,200.00
B
N43,000.00
C
N42,200.00
D
N40,000.00
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Correct Option: A
let the total amount be Nx i.e (\(\frac{1}{4}\))x + (\(\frac{1}{3}\))x + 72,000 = x
\(\frac{x}{4} + \frac{x}{4} + 72,000 = x\)
\(\frac{3x + 4x + 86,400}{12} = x\)
cross multiply to clear fraction
12x = 3x + 4x + 86,400
12x - 7x = 86,400
5x = 86,400
x - \(\frac{86,400}{5}\) = 172,800
amount spent on food = \(\frac{1}{4} \times 172,800\)
= N43,200
\(\frac{x}{4} + \frac{x}{4} + 72,000 = x\)
\(\frac{3x + 4x + 86,400}{12} = x\)
cross multiply to clear fraction
12x = 3x + 4x + 86,400
12x - 7x = 86,400
5x = 86,400
x - \(\frac{86,400}{5}\) = 172,800
amount spent on food = \(\frac{1}{4} \times 172,800\)
= N43,200
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