Question on: WAEC Physics - 2016
An aluminium cable of diameter 4 x 10-3m and resistivity 3.0 x 10-8(\omega)m has a resistance of 21(\Omega). Calculate the length of the cable. ((\pi = 3.14))
A
8.0 x 102m
B
8.8 x 103m
C
8.0 x 104m
D
8.8 x 104m
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Correct Option: B
R = (\frac{4eL}{\pid^2})
L = (\frac{R\pid^2}{4e})
= (\frac{21 \times 3.14(4 \times 10^{-3})^2}{4 \times 3.0 x 10^{-8}})
= 8.8 x 103m
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