Question on: WAEC Physics - 2004
An elastic string of force constant 200N m-1 is stretched through 0.8m within its elastic limit. Calculate the energy stored in the string
A
64.0J
B
80.0J
C
128.0J
D
160.0J
Ask EduPadi AI for a detailed answer
Correct Option: A
E = (\frac{1}{2}Ke^2)
= (\frac{1}{2} \times 200(0.8)^2 = 64J)
Add your answer
Please share this, thanks!
No responses