Question on: WAEC Physics - 2001
An electric bulb is rated 60W, 220V. Calculate the resistance of its filament when it is operating normally
A
296.7\(\Omega\)
B
400.0\(\Omega\)
C
512.2\(\Omega\)
D
806.7\(\Omega\)
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Correct Option: D
P = (\frac{v^2}{P} = \frac{220^2}{100} = 806.7\Omega)
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