Question on: WAEC Physics - 2006
An electric lamp rated 120W is used on a 240Vrms, calculate the resistance of its filament
A
480\(\Omega\)
B
360\(\Omega\)
C
60\(\Omega\)
D
2\(\Omega\)
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Correct Option: A
R = \(\frac{V^2}{P} = \frac{240^2}{120} = 480\Omega\)
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