An electron falls from an energy level of -5 44 - 942 - JAMB Physics 2024 Question
An electron falls from an energy level of -5.44eV to another energy level, E. If the emitted photon is of wavelength 5.68 x 10(^{-6})m, calculate the energy change. [ Plank's constant = 6.63 x 10(^{-34})Js, emitted radiation speed = 3.0 x 10(^8)ms(^{-1})]
A
1.49 x 10\(^{-20}\)J
B
1.49 x 10\(^{-19}\)J
C
3.49 x 10\(^{-20}\)J
D
3.49 x 10\(^{-19}\)J
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Correct Option: C
Here's how to solve this problem:
-
Identify the formula: The energy of a photon is given by E = hc/λ, where:
- E = energy of the photon
- h = Planck's constant (6.63 x 10⁻³⁴ Js)
- c = speed of light (3.0 x 10⁸ m/s)
- λ = wavelength (5.68 x 10⁻⁶ m)
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Plug in the values: E = (6.63 x 10⁻³⁴ Js * 3.0 x 10⁸ m/s) / 5.68 x 10⁻⁶ m
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