Question on: WAEC Physics - 2007
An external force of magnitude 100N acts on a particle of mass 0.15kg for 0.03s. Calculate the change in the speed of the particle
A
50ms-1
B
25ms-1
C
20ms-1
D
5ms-1
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Correct Option: C
a = \(\frac{F}{m} = \frac{100}{0.15} = 666.7\)
v = u + at
= 0 + 66.7 x 0.03
= 20m/s2
v = u + at
= 0 + 66.7 x 0.03
= 20m/s2
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