An object is placed 20 0cm in front of a conver... - WAEC Physics 2011 Question
An object is placed 20.0cm in front of a converging lens of focal length 15.0cm. Calculate its image distance
A
1.3cm
B
8.6cm
C
35.0cm
D
60.0cm
correct option: d
\(\frac{1}{v} = \frac{1}{f} - \frac{1}{U}\)
\(\frac{1}{15} - \frac{1}{20} = 60cm\)
\(\frac{1}{15} - \frac{1}{20} = 60cm\)
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