An object is placed directly below a glass bloc... - JAMB Physics 1994 Question
An object is placed directly below a glass block of thickness 3.0cm. Calculate the lateral displacement of the object if the refractive index of the glass is 1.5.
A
1.0cm
B
1.5cm
C
2.0cm
D
2.5cm
correct option: a
1.5 = \(\frac{3}{\text {apparent displacement}}\)
Apparent depth = 2cm
displacement = 3 - 2
= 1cm
Apparent depth = 2cm
displacement = 3 - 2
= 1cm
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