Question on: WAEC Physics - 2014
an observer hears an echo 1.26 seconds after blowing a whistle near a cliff. calculate the distance of the observer from the cliff. [speed of sound in air = 330ms-1]
A
104.4m
B
207.9m
C
415.8m
D
523.8m
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Correct Option: B
S = (\frac{vt}{2} = \frac{330 \times 1.26}{2} = 207.9)
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