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An observer stands 40 meters away from a buildi... - JSS3 Mathematics Trigonometric Ratios Question

An observer stands 40 meters away from a building and looks up at an angle of elevation of 35 degrees. Find the height of the building.

Given:

Horizontal distance (adjacent side, adj) = 40 meters

Angle of elevation (θ) = 35 degrees

To find the height (opposite side, opp):

tan(35∘)=opp40

opp=40⋅tan⁡(35∘)

Using a calculator: tan⁡(35∘)≈0.7002

opp≈40⋅0.7002=28.01 meters

So, the height of the building is approximately 28.01 meters.

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