An observer stands 40 meters away from a buildi... - JSS3 Mathematics Trigonometric Ratios Question
An observer stands 40 meters away from a building and looks up at an angle of elevation of 35 degrees. Find the height of the building.
Given:
Horizontal distance (adjacent side, adj) = 40 meters
Angle of elevation (θ) = 35 degrees
To find the height (opposite side, opp):
tan(35∘)=opp40
opp=40⋅tan(35∘)
Using a calculator: tan(35∘)≈0.7002
opp≈40⋅0.7002=28.01 meters
So, the height of the building is approximately 28.01 meters.
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