Question on: JSS3 Mathematics - Trigonometric Ratios

Given:

Horizontal distance (adjacent side, adj) = 40 meters

Angle of elevation (θ) = 35 degrees

To find the height (opposite side, opp):

tan(35∘)=opp40

opp=40⋅tan⁡(35∘)

Using a calculator: tan⁡(35∘)≈0.7002

opp≈40⋅0.7002=28.01 meters

So, the height of the building is approximately 28.01 meters.