An open-tube mercury manometer is used to measu... - JAMB Physics 2023 Question

The absolute pressure (\(P_{\text{abs}}\)) in the tank can be calculated using the equation \(P_{\text{abs}} = P_{\text{atm}} + \rho gh\), where:

- \(P_{\text{atm}}\) is the atmospheric pressure (given as \(101,325 \, \text{Pa}\)),
- \(\rho\) is the density of mercury (\(13,600 \, \text{kg/m}^3\)),
- \(g\) is the acceleration due to gravity (\(9.8 \, \text{m/s}^2\)),
- \(h\) is the height difference of the mercury column (\(0.25 \, \text{m}\)).

Substituting the values:

\[
P_{\text{abs}} = 101,325 + 13,600 \times 9.8 \times 0.25 \\
P_{\text{abs}} = 101,325 + 33,320 \\
P_{\text{abs}} = 134,645 \, \text{Pa}
\]

Therefore, the correct answer is: \(134,645 \, \text{Pa}\).