Question on: JAMB Physics - 1990
An organic pipe closed at one end is 80cm long. Determine the frequency of the fundamental note assuming that the speed of sound in air is 340ms-1
A
106Hz
B
213Hz
C
318Hz
D
425Hz
Ask EduPadi AI for a detailed answer
Correct Option: A
\(\lambda\) = 4L
= 4 x 80 = 320cm
F = \(\frac{V}{\lambda}\)
= \(\frac{340}{34 \times 10^2}\)
= 106Hz
= 4 x 80 = 320cm
F = \(\frac{V}{\lambda}\)
= \(\frac{340}{34 \times 10^2}\)
= 106Hz
Add your answer
Please share this, thanks!
No responses