At 2 0 atm pressure the volume of a gas is 4 0 ... - JAMB Chemistry 2023 Question

According to Boyle's Law, the relationship between pressure and volume for a given amount of gas at constant temperature is expressed as $P_1{V}_1=P_2{V}_2$.

Given:
- $P_1=2.0$ atm
- $V_1=4.0$ L
- $P_2=1.0$ atm (new pressure, reduced)
- $V_2$ is what we need to find.

Using the Boyle's Law formula, we can rearrange it to solve for $V_2$:
$$V_2=\frac{P_1\cdot V_1}{P_2}$$

Substitute the given values:
$$V_2=\frac{2.0\text{atm}\cdot 4.0\text{L}}{1.0\text{atm}}$$
$$V_2=8.0\text{L}$$

Therefore, the new volume of the gas at 1.0 atm pressure is 8.0 L