At 2 0 atm pressure the volume of a gas is 4 0 ... - JAMB Chemistry 2023 Question

According to Boyle's Law, the relationship between pressure and volume for a given amount of gas at constant temperature is expressed as \( P_1V_1 = P_2V_2 \).

Given:
- \( P_1 = 2.0 \) atm
- \( V_1 = 4.0 \) L
- \( P_2 = 1.0 \) atm (new pressure, reduced)
- \( V_2 \) is what we need to find.

Using the Boyle's Law formula, we can rearrange it to solve for \( V_2 \):
\[ V_2 = \frac{{P_1 \cdot V_1}}{{P_2}} \]

Substitute the given values:
\[ V_2 = \frac{{2.0 \, \text{atm} \cdot 4.0 \, \text{L}}}{{1.0 \, \text{atm}}} \]
\[ V_2 = 8.0 \, \text{L} \]

Therefore, the new volume of the gas at 1.0 atm pressure is 8.0 L