Question on: WAEC Physics - 2016
At a birthday party, the celebrant pops a corked fruit wine. If the cork shoots out of the bottle at an angle of 40o to the horizontal and travels a horizontal distance of 4.50m in 1.25s. Calculate the initial speed of the cork.
A
4.2ms-1
B
4.7ms-1
C
5.6ms-1
D
7.1ms-1
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Correct Option: B
R = Ucos\(\theta\) x t
U = \(\frac{R}{Cos \theta \times t}\)
= \(\frac{4.50}{Cos40N.25}\)
= 4.699m/s
U = \(\frac{R}{Cos \theta \times t}\)
= \(\frac{4.50}{Cos40N.25}\)
= 4.699m/s
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