Question on: JAMB Physics - 2013
At what depth below the sea-level would one experience a change of pressure equal to one atmosphere? Density of sea water = 1013kg-3, one atmosphere = 0.01 x 105Nm-2, g = 10ms-2
A
0.1m
B
1.0m
C
10.0m
D
100.0m
Ask EduPadi AI for a detailed answer
Correct Option: C
H = (\frac{P}{e_g})
H = (\frac{1.01 \times 10^5}{1013 \times 10})
H = 9.97
Add your answer
Please share this, thanks!
No responses