Question on: JAMB Mathematics - 2014
(\begin{array}{c|c}
Numbers & 1 & 2 & 3 & 4 & 5 & 6 \
\hline
Frequency & 18 & 22 & 20 & 16 & 10 & 14
\end{array})
The table above represents the outcome of throwing a die 100 times. What is the probability of obtaining at least a 4?
A
\(\frac{1}{5}\)
B
\(\frac{1}{2}\)
C
\(\frac{2}{5}\)
D
\(\frac{3}{4}\)
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Correct Option: C
Let E demote the event of obtaining at least a 4
Then n(E) = 16 + 10 + 14 = 40
Hence, prob (E) = (\frac{n(E)}{n(S)})
( = \frac{40}{100})
( = \frac{2}{5})
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