Question on: WAEC Physics - 2004
Calculate the energy stored in a 20(\mu F) capacitor. If the p.d between the plates is 40V
A
3.2 x 10-2J
B
1.6 x 10-2J
C
8.0 x 10-4J
D
4.0 x 10-4J
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Correct Option: B
W = (\frac{cv^2}{2} = \frac{20 \times 10^{-6} \times 40^{2}}{2})
= 1.6 x 10-2J
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