Question on: JAMB Physics - 2014
Calculate the escape velocity of a satellite launched from the earth's surface if the radius of the earth is 6.4x106m
A
25.3kms-1
B
4.2kms-1
C
4.0kms-1
D
11.3kms-1
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Correct Option: D
Vescape = \(\sqrt{2gR}\)
Vescape = \(\sqrt{2\times10\times6.4\times10^6}\)
Vescape = \(\sqrt{128000000}\)
Vescape = 11313.7085mS-1
Vescape = 11.313kmS-1
Vescape = \(\sqrt{2\times10\times6.4\times10^6}\)
Vescape = \(\sqrt{128000000}\)
Vescape = 11313.7085mS-1
Vescape = 11.313kmS-1
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