Question on: JAMB Physics - 2015
Calculate the gravitation force of attraction between two planets of 1024kg and 1027kg separated by a distance of 1020meters.
A
6.67N
B
6.56N
C
7.5N
D
8.6N
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Correct Option: A
F = (Gm1m2) ÷ r2
M1 = 1024Kg, M2 = 1027Kg , r = 102
(Note: the gravitational constant of G = \(6.67 × 10^{ 7ndash; 11}\) \( Nm^2/Kg^2 \)
F = \( (6.67 × 10^{– 11 + 24 + 27)} 10^40 = 6.67 × (10^40 ÷ 10^40)
= 6.67N
f = 6.67N
M1 = 1024Kg, M2 = 1027Kg , r = 102
(Note: the gravitational constant of G = \(6.67 × 10^{ 7ndash; 11}\) \( Nm^2/Kg^2 \)
F = \( (6.67 × 10^{– 11 + 24 + 27)} 10^40 = 6.67 × (10^40 ÷ 10^40)
= 6.67N
f = 6.67N
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