Calculate the logarithm to base 9 of 3-4 92 81 ... - JAMB Mathematics 2006 Question

(3^{-4}\times 9^2 \times 81^{-1}\

=log_9 (3^{-4}\times 9^2 \times 81^{-1})\

=log_9 \left(\frac{1}{3^4}\times 9^2 \times \frac{1}{81}\right)\

=log_9 \left(\frac{1}{81}\times \frac{81}{1}\times \frac{1}{81}\right)\

=log_9 \frac{1}{81}\

=log_9 \frac{1}{9^2}\

=log_9 9^{-2}\

=-2log_9 9\

-2 \times 1\

=-2)