Calculate the mean deviation of 5 3 0 7 2 1 - WAEC Mathematics 2015 Question
Calculate the mean deviation of 5, 3, 0, 7, 2, 1
A
0.0
B
2.0
C
2.5
D
3.0
correct option: b
mean = \(\bar{x}\) = \(\frac{\sum x}{n}\)
= \(\frac{5 + 3 + 0 + 7 + 2 + 1}{6}\)
\(\frac{18}{6}\) = 3
\(\begin{array}{c|c}
x & x - \bar{x} & |x - \bar{x}|\ \hline 5 & -2 & 2 \ \hline 3 & 0 & 0 \ \hline 0 & -3 & 3 \ \hline 7 & 4 & 4 \ \hline 2 & -1 & 1 \ \hline 1 & -2 & 2 \ \hline & & & \sum|x - \bar{x}| \ \hline & & & 12
\end{array}\)
hence, MD = \(\frac{\sum|x - \bar{x}}{n}|\)
\(\frac{12}{6}\)
= 2
= \(\frac{5 + 3 + 0 + 7 + 2 + 1}{6}\)
\(\frac{18}{6}\) = 3
\(\begin{array}{c|c}
x & x - \bar{x} & |x - \bar{x}|\ \hline 5 & -2 & 2 \ \hline 3 & 0 & 0 \ \hline 0 & -3 & 3 \ \hline 7 & 4 & 4 \ \hline 2 & -1 & 1 \ \hline 1 & -2 & 2 \ \hline & & & \sum|x - \bar{x}| \ \hline & & & 12
\end{array}\)
hence, MD = \(\frac{\sum|x - \bar{x}}{n}|\)
\(\frac{12}{6}\)
= 2
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