Calculate the mean deviation of 5 3 0 7 2 1 - WAEC Mathematics 2015 Question

mean = (\bar{x}) = (\frac{\sum x}{n})

= (\frac{5 + 3 + 0 + 7 + 2 + 1}{6})

(\frac{18}{6}) = 3

(\begin{array}{c|c}
x & x - \bar{x} & |x - \bar{x}|\ \hline 5 & -2 & 2 \ \hline 3 & 0 & 0 \ \hline 0 & -3 & 3 \ \hline 7 & 4 & 4 \ \hline 2 & -1 & 1 \ \hline 1 & -2 & 2 \ \hline & & & \sum|x - \bar{x}| \ \hline & & & 12
\end{array})

hence, MD = (\frac{\sum|x - \bar{x}}{n}|)

(\frac{12}{6})

= 2