Calculate the mid point of the line segment y -... - JAMB Mathematics 2014 Question

y - 4x + 3 = 0

When y = 0, 0 - 4x + 3 = 0

Then -4x = -3

x = 3/4

So the line cuts the x-axis at point (3/4, 0).

When x = 0, y - 4(0) + 3 = 0

Then y + 3 = 0

y = -3

So the line cuts the y-axis at the point (0, 3)

Hence the midpoint of the line y - 4x + 3 = 0, which lies between the x-axis and the y-axis is;

([\frac{1}{2}(x_1 + x_2), \frac{1}{2}(y_1 + y_2)])

([\frac{1}{2}(\frac{3}{4} + 0), \frac{1}{2}(0 + -3)])

([\frac{1}{2}(\frac{3}{4}), \frac{1}{2}(-3)])

([\frac{3}{8}, \frac{-3}{2}])