Question on: JAMB Mathematics - 1993
Calculate the standard deviation of the following data: 7, 8, 9, 10, 11, 12, 13.
A
2
B
4
C
10
D
11
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Correct Option: A
\(\begin{array}{c|c} x & x - x & (x - x)^2\ \hline 7 & -3 & 9\8 & -2 & 4 \9 & -1 & 1\10 & 0 & 1\11 & 1 & 1\ 12 & 2 & 4\13 & 3 & 9\ \hline & & 28\end{array}\)
S.D = \(\sqrt{\frac{\sum(x - x)^2}{N}}\)
= \(\sqrt{\frac{\sum d^2}{N}}\)
= \(\sqrt{\frac{28}{7}}\)
= \(\sqrt{4}\)
= 2
S.D = \(\sqrt{\frac{\sum(x - x)^2}{N}}\)
= \(\sqrt{\frac{\sum d^2}{N}}\)
= \(\sqrt{\frac{28}{7}}\)
= \(\sqrt{4}\)
= 2
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