Question on: WAEC Physics - 1992
Calculate the time in which 4.8 kJ of energy would be expended when an electric heater of resistance 1.8 x 103Ω is used on a 240 V mains supply. (Neglect heat losses to the surrounding).
A
150.0s
B
90.0s
C
36.0s
D
20.0s
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Correct Option: A
E = V2t/R
t =
ER/V2 =
4800 x 1.8 x 103/240 x 240 = 150s
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