Calculate the upthrust on an object of volume 50cm3 which is immersed in liquid of density 103kgm-3 [g = 10ms-2]
Correct Option:
C
Upthrust = change in weight
density = \(\frac{\text{mass}}{\text{volume}}\)
Mass of liquid displaced = Density of Liquid × Volume;
= 103 × 50 × 10− 6m3
= 0.05kg
(Note that the volume of 50cm3 was converted to m3 by multiplying by 106) i.e 50cm3 = 50 × 10−6m3)
Since mass displaced = 0.05kg
Upthrust = mg = 0.05 × 10
= 0.5N
density = \(\frac{\text{mass}}{\text{volume}}\)
Mass of liquid displaced = Density of Liquid × Volume;
= 103 × 50 × 10− 6m3
= 0.05kg
(Note that the volume of 50cm3 was converted to m3 by multiplying by 106) i.e 50cm3 = 50 × 10−6m3)
Since mass displaced = 0.05kg
Upthrust = mg = 0.05 × 10
= 0.5N