CH2S g O2 g 2Cn SO2 g What is the change in the... - JAMB Chemistry 2017 Question
CH2S(g) + O2(g) → 2Cn + SO2(g)
What is the change in the oxidation number of copper in the reaction?
What is the change in the oxidation number of copper in the reaction?
A
0 to + 2
B
0 to + 1
C
C + 1 to 0
D
+ 2 to + 1
correct option: c
In the reactant;
Cu2S
2 Cu - 2(1) = 0
2 Cu = 2
Cu = \(\frac{2}{2}\)
Cu = +1
In the product, Cu
Cu = O
The oxidation number of Cu in Cu2S and Cu respectively is +1 and 0 respectively
Cu2S
2 Cu - 2(1) = 0
2 Cu = 2
Cu = \(\frac{2}{2}\)
Cu = +1
In the product, Cu
Cu = O
The oxidation number of Cu in Cu2S and Cu respectively is +1 and 0 respectively
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