Question on: JAMB Mathematics - 2013
Convert 2710 to another number in base three
A
10013
B
10103
C
11003
D
10003
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Correct Option: D
\(\begin{array}{c|c}
3 & \text{27 rem 0} \\ \hline
3 & \text{ 9 rem 0} \\ \hline
3 & \text{ 3 rem 0} \\ \hline
3 & \text{ 1 rem 1}\\ \hline
& 0
\end{array}\)
Hence the correct answer is 10003
3 & \text{27 rem 0} \\ \hline
3 & \text{ 9 rem 0} \\ \hline
3 & \text{ 3 rem 0} \\ \hline
3 & \text{ 1 rem 1}\\ \hline
& 0
\end{array}\)
Hence the correct answer is 10003
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