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Cr2O72- aq 14H aq 6l- aq 2Cr3 aq 3l g 7H2O I Th... - JAMB Chemistry 1995 Question

Cr2O72-(aq) + 14H+(aq) + 6l-(aq) → 2Cr3+(aq) + 3l(g) + 7H2O(I).
The change in the oxidation number of oxygen in the equation above is?
A
0
B
1
C
2
D
7
correct option: a
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