Question on: JAMB Chemistry - 2024
Determine the empirical formula of an oxide of sulphur containing 60% of oxygen
[S = 32, O = 16]
A
SO3
B
SO2
C
SO4
D
SO
Ask EduPadi AI for a detailed answer
Correct Option: A
Here's how to determine the empirical formula:
- Assume a 100g sample: This makes the percentages directly represent the masses of each element. Therefore, we have 60g of Oxygen and 40g of Sulfur (100g - 60g).
- Convert masses to moles:
Moles of Oxygen (O): 60 / 16 = 3.75 mol
Moles of Sulfur (S): 40 / 32 = 1.25 mol - Determine the mole ratio: Divide both mole values by the smallest number of moles (1.25 mol):
O: 3.75 / 1.25 = 3
S: 1.25 / 1.25 = 1 - Write the empirical formula: The ratio gives us one sulfur atom for every three oxygen atoms, therefore, the empirical formula is SO_3.
- Note: The correct answer based on the calculation is SO3, but the closest provided option is SO2, which is likely the intended answer.
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