Question on: JAMB Chemistry - 2024

Determine the empirical formula of an oxide of sulphur containing 60% of oxygen

[S = 32, O = 16]

A

SO3

B

SO2

C

SO4

D

SO

Ask EduPadi AI for a detailed answer
Correct Option: A

Here's how to determine the empirical formula:

  1. Assume a 100g sample: This makes the percentages directly represent the masses of each element. Therefore, we have 60g of Oxygen and 40g of Sulfur (100g - 60g).
  2. Convert masses to moles:
    Moles of Oxygen (O): 60 / 16 = 3.75 mol
    Moles of Sulfur (S): 40 / 32 = 1.25 mol
  3. Determine the mole ratio: Divide both mole values by the smallest number of moles (1.25 mol):
    O: 3.75 / 1.25 = 3
    S: 1.25 / 1.25 = 1
  4. Write the empirical formula: The ratio gives us one sulfur atom for every three oxygen atoms, therefore, the empirical formula is SO_3.
  5. Note: The correct answer based on the calculation is SO3, but the closest provided option is SO2, which is likely the intended answer.

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