Determine the HCF of 28 and 42 - JSS2 Mathematics Factors and Multiples Question
Determine the HCF of 28 and 42.
The prime factorization of 28 is 2x2×7x1
The prime factorization of 42 is 2x1×3x1×7x1
The HCF is 2x1×7x1=2×7=14
So, HCF(28, 42) = 14.
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