Question on: JAMB Mathematics - 1998
Differentiate (\frac{x}{cosx}) with respect to x
A
1 + x sec x tan x
B
1 + sec2 x
C
cos x + x tan x
D
x sec x tan x + secx
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Correct Option: D
let y = (\frac{x}{cosx}) = x sec x
y = u(x) v (x0
(\frac{dy}{dx}) = U(\frac{dy}{dx}) + V(\frac{du}{dx})
dy x [secx tanx] + secx
x = x secx tanx + secx
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