Question on: JAMB Mathematics - 2006
Differentiate (x2 - 1/x)2 with respect to x
A
4x2 - 4x - 2/x
B
4x2 - 2 + 2/x3
C
4x2 - 2 - 2/x3
D
4x2 - 3x + 2/x
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Correct Option: C
y = (x2 - 1/x)2
y = (x2 - 1/x)(x2 - 1/x)
y = x4 - x - x + 1/x2
y = x4 - 2x + 1/x2
y= x4 - 2x + x-2
dy/dx = 4x2 - 2 - 2x-3
= 4x2 - 2 - 2/x3
y = (x2 - 1/x)(x2 - 1/x)
y = x4 - x - x + 1/x2
y = x4 - 2x + 1/x2
y= x4 - 2x + x-2
dy/dx = 4x2 - 2 - 2x-3
= 4x2 - 2 - 2/x3
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