Question on: JAMB Mathematics - 1998
Evaluate [\(\frac{1}{0.03}\) \(\div\) \(\frac{1}{0.024}\)]-1 correct to 2 decimal places
A
3.76
B
1.25
C
0.94
D
0.75
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Correct Option: B
[\(\frac{1}{0.03}\) + \(\frac{1}{0.024}\)]
= [\(\frac{1}{0.03 \times 0.024}\)]-1
= [\(\frac{0.024}{0.003}\)]-1
= \(\frac{0.03}{0.024}\)
= \(\frac{30}{24}\) = 1.25
= [\(\frac{1}{0.03 \times 0.024}\)]-1
= [\(\frac{0.024}{0.003}\)]-1
= \(\frac{0.03}{0.024}\)
= \(\frac{30}{24}\) = 1.25
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