Question on: JAMB Mathematics - 2008
Evaluate \(\int ^{2}_{1}\)(6x2 - 2x)dx
A
16
B
13
C
12
D
11
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Correct Option: D
\(\int ^{2}_{1}\)(6x2 - 2x)dx
= [\(\frac{6x^3}{3} - \frac{2x^2}{2}\)]2
= [2x3 - x2]2
= (2(2)3 - 4 - 2 + 1
= 16 - 4 - 2 + 1
= 17 - 6
= 11
= [\(\frac{6x^3}{3} - \frac{2x^2}{2}\)]2
= [2x3 - x2]2
= (2(2)3 - 4 - 2 + 1
= 16 - 4 - 2 + 1
= 17 - 6
= 11
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