Question on: JAMB Mathematics - 2014
Evaluate (\int \sin 2x dx)
A
cos 2x + k
B
\(\frac{1}{2}\)cos 2x + k
C
\(-\frac{1}{2}\)cos 2x + k
D
-cos 2x + k
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Correct Option: C
(\int \sin 2x dx = \frac{1}{2} (-\cos 2x) + k)
(- \frac{1}{2} \cos 2x + k)
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