Question on: JAMB Mathematics - 2003
Evaluate (\int^{2} _{3}(x^2 - 2x)dx)
A
4
B
2
C
4/3
D
1/3
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Correct Option: C
(\int^{2} {3}(x^2 - 2x)dx=\left[\frac{x^3}{3}-\frac{2x^2}{2}\right ]^{2}{3}\left[\frac{x^3}{3}-x^2 + C\right ]^{2}_{3}\left[\frac{3^3}{3}-3^2 + C \right ]-\left[\frac{2^3}{3}-2^2 + C \right ]\9-9-\left[\frac{8}{3}-4 \right ]=\frac{-8}{3}+4=\frac{4}{3})
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