Evaluate int 2 3 x 2 - 2x dx - JAMB Mathematics 2003 Question
Evaluate (\int^{2} _{3}(x^2 - 2x)dx)
A
4
B
2
C
4/3
D
1/3
Ask EduPadi AI...
Correct Option: C
(\int^{2} {3}(x^2 - 2x)dx=\left[\frac{x^3}{3}-\frac{2x^2}{2}\right ]^{2}{3}\left[\frac{x^3}{3}-x^2 + C\right ]^{2}_{3}\left[\frac{3^3}{3}-3^2 + C \right ]-\left[\frac{2^3}{3}-2^2 + C \right ]\9-9-\left[\frac{8}{3}-4 \right ]=\frac{-8}{3}+4=\frac{4}{3})
Please share this, thanks:
#JAMB #JAMB
Add your answer
No responses