Evaluate int 2 3 x 2 - 2x dx - JAMB Mathematics 2003 Question
Evaluate \(\int^{2} _{3}(x^2 - 2x)dx\)
A
4
B
2
C
4/3
D
1/3
correct option: c
\(\int^{2} _{3}(x^2 - 2x)dx\=\left[\frac{x^3}{3}-\frac{2x^2}{2}\right ]^{2}_{3}\\left[\frac{x^3}{3}-x^2 + C\right ]^{2}_{3}\\left[\frac{3^3}{3}-3^2 + C \right ]-\left[\frac{2^3}{3}-2^2 + C \right ]\9-9-\left[\frac{8}{3}-4 \right ]\=\frac{-8}{3}+4\=\frac{4}{3}\)
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