Question on: JAMB Mathematics - 2024
Evaluate \(\int (\cos4x + \sin3x) dx\)
A
sin4x - cos3x + k
B
sin4x + cos3x + k
C
\(\frac{1}{4}\)sin4x - \(\frac{1}{3}\)cos3x + k
D
\(\frac{1}{4}\)sin4x + \(\frac{1}{3}\)cos3x + k
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Correct Option: C
The integral of each term:
- ∫cos4x dx = sin4x / 4
- ∫sin3x dx = -cos3x / 3
Therefore:
∫(cos4x + sin3x) dx = (1/4) sin4x - (1/3) cos3x + C
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